-
FlexPro
- Auf einen Blick
- Features & Optionen
- Einsatzgebiete
- Alle Vorteile
- Neu in FlexPro 2021
- FlexPro gratis testen
- FlexPro View OEM Freeware
- Kaufberatung
- Login
- Language
- +49 6894 929600
- infoweisang.com
- Google Maps
- Produkte
- News
- Support
- Unternehmen
- Jobs
- Kontakt
- Login
- Language
- +49 6894 929600
- infoweisang.com
- Google Maps
selecting positive values
- Dieses Thema hat 5 Antworten sowie 2 Teilnehmer und wurde zuletzt vor vor 14 Jahren, 1 Monat von mac ye aktualisiert.
-
AutorBeiträge
-
November 9, 2010 um 2:23 am Uhr #12452mac yeMitglied
I got a problem in filtering positive values from a data set.
background:
A is a data set with pos and neg values. and I want to selet all the positive values and set all negative values to 0
so I create a data set B with same number of colums and initial value as 0I wrote a script in a function like this:
Dim i
For i=0 To 8000 Do
If A < 0 Then
B==A
End
EndBut it returns "no value"
Would you please give me an example for this?November 9, 2010 um 2:23 am Uhr #8131mac yeMitgliedI got a problem in filtering positive values from a data set.
background:
A is a data set with pos and neg values. and I want to selet all the positive values and set all negative values to 0
so I create a data set B with same number of colums and initial value as 0I wrote a script in a function like this:
Dim i
For i=0 To 8000 Do
If A < 0 Then B[i]==A[i] End End But it returns "no value" Would you please give me an example for this?November 9, 2010 um 5:39 pm Uhr #8747Bernhard KantzTeilnehmerYou have to use = instead of ==.
But it’s better and faster to use the ValuesBelow-function and the index operator.Example:
Dim B = A B[ValuesBelowLevel(A, 0, EVENT_INDEX)] = 0
November 9, 2010 um 6:57 pm Uhr #8748mac yeMitgliedhello, thank you for your reply!
when I use the valusebelow func, it replies:
index assignment to signals, signal serials.. are not allowed. assign the components seperately.
So do you have any further recommendation?
Thank you!
November 9, 2010 um 11:58 pm Uhr #8749Bernhard KantzTeilnehmerNovember 10, 2010 um 2:31 am Uhr #8750mac yeMitgliedThank you! It works!
-
AutorBeiträge
- Du musst angemeldet sein, um auf dieses Thema antworten zu können.