Filter coefficient

[HerveM1234]

Hi,

I’m trying to apply the following transfer function to FlexPro9 filter:

G(s)= 43498.1684982
——————————————————————————–
s2+213.553113553s+17857.1428571

I do not really understand the way to apply these coefficient in the Filter formula. Filter(Signal,NumFilter,DenomFilter)
Thanks for your help.

rv

[HerveM1234]

Hi,

I’m trying to apply the following transfer function to FlexPro9 filter:

G(s)= 43498.1684982
——————————————————————————–
s2+213.553113553s+17857.1428571

I do not really understand the way to apply these coefficient in the Filter formula. Filter(Signal,NumFilter,DenomFilter)
Thanks for your help.

rv

[Bernhard Kantz]

The coefficients to be fed into the Filter function are exactly the coefficients of the numerator / denominator polynom of the rational system function.
To apply the filter from the question, use for example

Dim b = { 43498.1684982, 0.0, 0.0 }
Dim a = { 17857.1428571, 213.553113553, 1.0 }

Filter(, b, a)

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[HerveM1234]

Thanks for your reply,
but it doesn’t work.
In the transfer function given in example : ‘s’ is the continuous Laplace variable isn’t it ?

[Autor]

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